Quickly parse [http[s]://][username[:password]@]hostname[:port][/path]

username_parse.py

# [http[s]://][username[:password]@]hostname[:port][/path]
# from username_parse import parse as parse_u
# EXAMPLE USAGE:
# username,hostname,password,port,path,protocol = parse_u(argv[1])
# username = parse_u(argv[1])[0]
# ip,password = parse_u(argv[1])[1:3]
# host,port = parse_u(argv[1])[1:4:2]
# Not intended for use without a hostname

#Conceptual Lambda (vestigial,
# but uncommented in case you want to import it):
s=lambda h,c='@',r=1: getattr(h, 'rsplit' if r else 'split')(c)

def parse(h,username=None,password=None,protocol=None,port=None,path=None):
	if '://' in h[:10]: #Change 10 to 8 if you want
		protocol,h=h.split('://',1)
	if '@' in h:
		username,h=h.rsplit('@',1)
		if ':' in username:
			username,password=username.split(':',1)
#			print(         "\x1b[31;1mInsecure password entry method\x1b[0m")
#			raise DeprecationWarning("Insecure password entry method")
	if '/' in h:
		h,path=h.split('/',1)
		path='/'+path
	if ':' in h:
		h,port=h.split(':')
		port=int(port)
	
#	if protocol and not port:
#		port=(80 if protocol=='http' else 443 if protocol=='https' else None)
#	elif port and not protocol:
#		protocol=('http' if port==80 else 'https' if port==443 else None)
	
	return username,h,password,port,path,protocol