Push private repository with submodules to DEIS (assuming the repo already has been ``deis create projectname``'d)

push_submodule_to_DEIS.sh

#!/usr/bin/env bash

export GIT_FLAGS=$*

OLD_BRANCH="master" # $(git $GIT_FLAGS rev-parse --abbrev-ref HEAD)
echo $OLD_BRANCH
TEMP_BRANCH="deis_build"
git $GIT_FLAGS branch --force $TEMP_BRANCH && git $GIT_FLAGS checkout --force $TEMP_BRANCH
 
git $GIT_FLAGS submodule status | cut -d' ' -f3 | xargs --no-run-if-empty -I{} bash -c "git $GIT_FLAGS config -f .git/config --remove-section submodule.{}" && find -type f -name .git -o -type f -name .gitmodules | xargs --no-run-if-empty rm -f && rm -rf .git/modules/* && rm -f .git/index && git $GIT_FLAGS add -A && git $GIT_FLAGS commit -m"flattened" && git $GIT_FLAGS push deis $TEMP_BRANCH:master --force
MAIN_EXIT_CODE=$?
 
#cleanup
git $GIT_FLAGS checkout --force $OLD_BRANCH
git $GIT_FLAGS branch -D $TEMP_BRANCH
git $GIT_FLAGS submodule update --init --recursive
 
exit $MAIN_EXIT_CODE

Note that this command will remove any uncommited files (and probably unstaged as well)

adds support for push_submodule_to_DEIS.sh -C "gitrepo" (or any arbitrary general git argument) but it should still be backwards compat

xargs --no-run-if-empty

always rm -f incase missing

how do you make this always work again, despite what state it was left in last time?

should always be used with a "wipe clean and re-clone" policy so that isn't effected by the previous state (especially after fails)