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Cross product of an array against itself n times
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| def cross values, n = 3 | |
| Array.new(n, values).inject do |acc, i| | |
| acc.product(i).map(&:flatten) | |
| end | |
| end | |
| require 'set' | |
| describe do | |
| it "should cross itself" do | |
| arr = [0, 128] | |
| out = [ | |
| [0, 0, 0], | |
| [0, 0, 128], | |
| [0, 128, 0], | |
| [0, 128, 128], | |
| [128, 0, 0], | |
| [128, 0, 128], | |
| [128, 128, 0], | |
| [128, 128, 128], | |
| ] | |
| cross(arr).to_set.should eq out.to_set | |
| end | |
| end |
JonathonMA
commented
Aug 31, 2013
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