oddArray

//ARRAY: Given an array of ints of ODD length, 
//look at the first, last,
//and middle values in the array and return the largest. The array length will be a least 1. 

import java.util.Scanner;

public class oddArray{
	public static void main(String[] args) {

		Scanner input = new Scanner(System.in);

		int places = input.nextInt();

	
		if (places%2 == 0){
			System.out.println("Please introduce an odd number");
		}
		else{
			int [] myArray = new int [places];
			for (int i=0; i<myArray.length; i++) {
				System.out.println("Enter array item " + i);
				myArray[i] = input.nextInt();
			}
			int largestnumber = checkFirstMidLast(myArray);
			System.out.println("Largest number is:");
			System.out.println(largestnumber);
		}

	}
	 	
	public static int checkFirstMidLast(int[] myArray) {
	 	int a = myArray [0];
	 	int b = myArray[(myArray.length+1)/2-1];
	 	int c = myArray[myArray.length -1];
	 	int biggest = 0;

		if (a > b && a>c){
			biggest = a;
		}
		else if (b>a && b>c ) {
			biggest = b;	
		}
		else if (c>b && c>a){
			biggest = c;
		}
		return biggest;		
	}
}