Write a function that takes an array of daily temperatures and returns an array where each element is the number of days you would have to wait until a warmer temperature. If there is no future day for which this is possible, put 0 instead.

dailyTemperatures.js

const dailyTemp = (arr) => {

  const answer = []
  for (let i = 0; i < arr.length; i++) {
    const current = arr[i];
    const higher = arr.slice(i).findIndex((item) => item > current);
    higher >= 0 ? answer.push(higher) : answer.push(0);
  }
  return answer;
}

console.log(dailyTemp([70, 70, 70, 75]));
console.log(dailyTemp([90, 80, 70, 60]));
console.log(dailyTemp([73, 74, 75, 71, 69, 72, 76, 73]));