Created
February 1, 2014 02:56
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#include <cstdio> | |
#include <algorithm> | |
#include <cmath> | |
using namespace std; | |
int N,x[200001],y[200001]; | |
double a_dis[200001],b_dis[200001]; | |
int ax,ay,bx,by,Q,R1,R2; | |
int BS (int R,double dis[]) | |
{ | |
int left = 0, right = N-1; | |
while (left != right){ | |
int mid = (left+right+1)/2; | |
if (dis[mid] > R) right = mid-1; | |
else left = mid; | |
} | |
return left+1; //回傳為數量,因此是index+1 | |
} | |
int main() | |
{ | |
freopen ("input.txt","rt",stdin); | |
int Case = 1; | |
while (scanf("%d",&N)){ | |
if (!N) break; | |
for (int i=0; i<N; i++) scanf("%d %d",&x[i],&y[i]); | |
scanf("%d %d %d %d %d",&ax,&ay,&bx,&by,&Q); | |
for (int i=0; i<N; i++) { | |
a_dis[i] = sqrt (pow(x[i]-ax,2) + pow(y[i]-ay,2)); | |
b_dis[i] = sqrt (pow(x[i]-bx,2) + pow(y[i]-by,2)); | |
} | |
sort (a_dis,a_dis+N); | |
sort (b_dis,b_dis+N); | |
printf("Case %d:\n",Case++); | |
while (Q--){ | |
scanf("%d %d",&R1,&R2); | |
int ans = N - BS(R1,a_dis) - BS(R2,b_dis); | |
if (ans >= 0) printf("%d\n",ans); | |
else printf("0\n"); | |
} | |
} | |
return 0; | |
} |
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