Created
February 22, 2014 15:44
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| #include <cstdio> | |
| #include <iostream> | |
| #include <queue> | |
| #include <vector> | |
| #include <map> | |
| using namespace std; | |
| map<string, int> Map; | |
| vector<string> toPoint[10001]; | |
| void BFS (string Start, string End) | |
| { | |
| queue<string> Q; | |
| Q.push(Start); | |
| int visit[10001] = {0}; | |
| visit[Map[Start]] = 1; | |
| // 標準BFS演算法 | |
| string cur; | |
| bool FindedEnd = 0; | |
| while (!Q.empty() && !FindedEnd) { | |
| cur = Q.front(); | |
| Q.pop(); | |
| for (const auto &nxt : toPoint[Map[cur]]) { | |
| if (visit[Map[nxt]] == 0) { | |
| // 將走過的步數存下來,等等逆向的時候會用到 | |
| visit[Map[nxt]] = visit[Map[cur]] + 1; | |
| if (nxt == End) { | |
| FindedEnd = 1; | |
| break; | |
| } | |
| Q.push(nxt); | |
| } | |
| } | |
| } | |
| // 逆向走回起點並將該路徑存在Ans | |
| int step_count = visit[Map[End]]; | |
| vector<char> Ans = {End[0]}; | |
| cur = End; | |
| while (step_count != 1) { | |
| for (const auto &nxt : toPoint[Map[cur]]) { | |
| if (visit[Map[nxt]] == step_count - 1) { | |
| Ans.push_back(nxt[0]); | |
| --step_count; | |
| cur = nxt; | |
| break; | |
| } | |
| } | |
| } | |
| for (auto i = Ans.end() - 1; i != Ans.begin(); --i) | |
| cout << *i; | |
| cout << Ans[0] << endl; | |
| } | |
| int main() | |
| { | |
| // freopen("input.txt","rt",stdin); | |
| ios::sync_with_stdio(false); | |
| int Case, M, N; | |
| cin >> Case; | |
| while (Case--) { | |
| Map.clear(); | |
| for (auto &v : toPoint) v.clear(); | |
| string s1, s2; | |
| cin >> M >> N; | |
| for (int i = 0, j = 1; i < M; ++i) { | |
| cin >> s1 >> s2; | |
| if (!Map[s1]) Map[s1] = j++; | |
| if (!Map[s2]) Map[s2] = j++; | |
| toPoint[Map[s1]].push_back(s2); | |
| toPoint[Map[s2]].push_back(s1); | |
| } | |
| for (int i = 0; i < N; ++i) { | |
| cin >> s1 >> s2; | |
| BFS (s1, s2); | |
| } | |
| if (Case) cout << endl; | |
| } | |
| return 0; | |
| } |
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