Created
April 3, 2014 11:39
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#include <cstdio> | |
#include <queue> | |
using namespace std; | |
int Energy[101]; | |
int toNxt[101][101]; | |
bool SPFA(const int N); | |
int main() | |
{ | |
int N; | |
while (scanf("%d", &N) && N != -1) { | |
for (int i = 1; i <= N; ++i) { | |
// 用toNxt[i][0]來存i能前往哪些點的數量 | |
scanf("%d %d", &Energy[i], &toNxt[i][0]); | |
for (int j = 1; j <= toNxt[i][0]; ++j) | |
scanf("%d", &toNxt[i][j]); | |
} | |
if (SPFA(N)) | |
puts("winnable"); | |
else | |
puts("hopeless"); | |
} | |
} | |
bool SPFA(const int N) | |
{ | |
queue<int> Q; | |
int inQueue[101] = {0}; | |
int Dis[101] = {0}; | |
int Count = 0; // avoid infinite cycle | |
Dis[1] = 100, inQueue[1] = true; | |
Q.push(1); | |
while (!Q.empty()) { | |
int now = Q.front(); | |
inQueue[now] = false; | |
Q.pop(); | |
for (int i = 1; i <= toNxt[now][0]; ++i) { | |
int nxt = toNxt[now][i]; | |
int tmp = Dis[now] + Energy[nxt]; | |
if (tmp > Dis[nxt]) { | |
Dis[nxt] = tmp; | |
if (!inQueue[nxt]) { | |
Q.push(nxt); | |
inQueue[nxt] = true; | |
++Count; | |
} | |
} | |
} | |
if (Dis[N] > 0) return true; | |
if (Count > 1000000) return false; | |
} | |
return false; | |
} |
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