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February 4, 2019 12:26
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# Get the keys that don't exist in both dicts | |
missing = set(val1.keys()).symmetric_difference(set(val2.keys())) | |
# Get the keys that DO exist in both | |
found = set(val1.keys()) & set(val2.keys()) | |
diff = len(missing) | |
matching = len(found) | |
for resource in missing: | |
# Lets log the keys that aren't in both dicts and report which one it belonged to | |
msg = 'Resource {0} not found in {1}' | |
if not val1.get(resource): | |
logger.critical(crayons.yellow(msg.format(resource, 'dict1'))) | |
elif not val2.get(resource): | |
logger.critical(crayons.yellow(msg.format(resource, | |
'dict2'))) | |
for resource in found: | |
# Now lets go through each key in the dict and compare their values | |
obj1 = [val1[resource]] | |
obj2 = [val2[resource]] | |
for resource2, resource1 in izip(obj2, obj1): | |
# now the next layer of the dict lets get their keys and do the same comparison | |
shared_keys = set(resource1.keys()) & set(resource2.keys()) | |
untested_keys =set(resource1.keys()).symmetric_difference(set( | |
resource2.keys())) | |
if len(shared_keys) < 2: | |
raise Exception('I require more than 2 keys to compare') | |
obj_differences = {'objects': []} | |
for key in shared_keys: | |
res1, res2 = set_overrides(resource1[key], | |
resource2[key], key) | |
if res1 != res2: | |
# Ugly because order of item args matters | |
obj_differences['objects'].append({key: | |
{'dict1': resource1[key], | |
'dict2': resource2[key]}}) | |
diff += 1 | |
if obj_differences['objects']: | |
msg = 'Resource value not equal in both: {0}' | |
logger.critical(crayons.yellow(msg.format(resource))) | |
logger.critical(crayons.yellow('\n {0}'.format(pformat( | |
obj_differences)))) |
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