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July 3, 2017 13:58
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Take the digits 1,2,3 up to 9 in numerical order and put either a plus sign or a minus sign or neither between the digits to make a sum that adds up to 100. For example, one way of achieving this is: 1 + 2 + 34 - 5 + 67 - 8 + 9 = 100, which uses six plusses and minuses. What is the fewest number of plusses and minuses you need to do this?
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# pow(3, 8) = 6561 | |
options = ['', '+', '-'] | |
for i in options: | |
for j in options: | |
for k in options: | |
for l in options: | |
for m in options: | |
for n in options: | |
for o in options: | |
for p in options: | |
if eval('1' + i + '2' + j + '3' + k + '4' + l + '5' + m + '6' + n + '7' + o + '8' + p + '9') == 100: | |
print '1' + i + '2' + j + '3' + k + '4' + l + '5' + m + '6' + n + '7' + o + '8' + p + '9' | |
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