Created
December 5, 2016 09:41
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Synchronous Shopping solution
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#include <cmath> | |
#include <cstdio> | |
#include <vector> | |
#include <iostream> | |
#include <algorithm> | |
#include <queue> | |
#include <list> | |
#include <bitset> | |
using namespace std; | |
struct State { | |
int p, l, f; | |
State(int pin, int lin, int fin) : p(pin), l(lin), f(fin) {} | |
}; | |
bool operator < (const State& l, const State& r) { | |
return l.l > r.l; | |
} | |
void visit(vector< list< pair<int, int> > >& adj, vector<int>& fishMask, vector<vector<int>>& res) { | |
priority_queue<State> pq; | |
pq.push( State(0, 0, fishMask[0]) ); | |
while (!pq.empty()) { | |
State s = pq.top(); pq.pop(); | |
if (s.l < res[s.p][s.f]) { | |
res[s.p][s.f] = s.l; | |
for (auto v : adj[s.p]) { | |
pq.push( State(v.first, s.l + v.second, s.f | fishMask[v.first]) ); | |
} | |
} | |
} | |
} | |
int main() { | |
int N, M, T; | |
cin >> N >> M >> T; | |
N; M; T; | |
vector<int> fishMask(N, 0); | |
for (int i = 0; i < N; ++i) { | |
int n; | |
cin >> n; | |
while (n > 0) { | |
int t; | |
cin >> t; | |
--t; | |
fishMask[i] |= 1 << t; | |
--n; | |
} | |
} | |
vector< list< pair<int, int> > > adj(N); | |
for (int i = 0; i < M; ++i) { | |
int u,v,w; | |
cin >> u >> v >> w; | |
--u; --v; | |
adj[u].push_back( make_pair(v, w) ); | |
adj[v].push_back( make_pair(u, w) ); | |
} | |
int maxFishMask = 1<<(T); | |
vector< vector<int> > res(N, vector<int>(maxFishMask, 1e6)); | |
visit(adj, fishMask, res); | |
int minPath = 1e6; | |
for (int i = 0; i < maxFishMask; ++i) | |
for (int j = i; j < maxFishMask; ++j) | |
if ((i | j) == maxFishMask-1) { | |
minPath = min(minPath, max(res[N-1][i], res[N-1][j])); | |
} | |
cout << minPath; | |
return 0; | |
} |
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