Created
December 18, 2013 18:52
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Write an algorithm such that if an element in an MxN matrix is 0, its entire row and column is set to 0.
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| #include<iostream> | |
| using namespace std; | |
| int main() | |
| { | |
| int m = 3; | |
| int n = 3; | |
| int array[3][3] = {{1,2,3},{4,5,6}, {7,8,9}}; | |
| int row[3*3]; | |
| int column[3*3]; | |
| int count = 0; | |
| for(int row=0; row < m; row++) | |
| { | |
| for(int col=0; col < n; col++) | |
| { | |
| cout << array[row][col]; | |
| } | |
| cout << endl; | |
| } | |
| for(int i=0; i < m; i++) | |
| { | |
| for(int j=0; j < n; j++) | |
| { | |
| if(array[i][j] == 0) | |
| { | |
| row[count] = i; | |
| column[count] = j; | |
| count++; | |
| } | |
| } | |
| } | |
| cout << endl << endl; | |
| for(int i=0; i < count; i++) | |
| { | |
| for(int j=0; j < n; j++) | |
| { | |
| if(row[i] + j < 3) | |
| { | |
| array[row[i] + j][column[i]] = 0; | |
| } | |
| if(row[i] - j >= 0) | |
| { | |
| array[row[i] - j][column[i]] = 0; | |
| } | |
| } | |
| for(int j=0; j < n; j++) | |
| { | |
| if(column[i] + j < 3) | |
| { | |
| array[row[i]][column[i]+j] = 0; | |
| } | |
| if(row[i] - j >= 0) | |
| { | |
| array[row[i]][column[i]-j] = 0; | |
| } | |
| } | |
| } | |
| for(int row=0; row < m; row++) | |
| { | |
| for(int col=0; col < n; col++) | |
| { | |
| cout << array[row][col]; | |
| } | |
| cout << endl; | |
| } | |
| return 0; | |
| } |
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