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1. List employees (names) who have a bigger salary than their boss | |
SELECT | |
e.`name` | |
FROM | |
employees AS e | |
INNER JOIN employees AS b ON e.bossid = b.employeeid | |
WHERE | |
e.salary > b.salary | |
2. List employees who have the biggest salary in their departments | |
SELECT | |
employees.`name` | |
FROM | |
employees | |
GROUP BY | |
employees.departmentid | |
ORDER BY | |
employees.salary ASC | |
3. List departments that have less than 3 people in it | |
SELECT | |
departments.`name` | |
FROM | |
departments | |
LEFT JOIN employees ON employees.departmentid = departments.departmentid | |
GROUP BY | |
departments.departmentid | |
HAVING | |
COUNT(*) < 3 | |
4. List all departments along with the number of people there (tricky - people often do an "inner join" leaving out empty departments) | |
SELECT | |
departments.`name`, | |
Count(employees.employeeid) as count | |
FROM | |
departments | |
LEFT JOIN employees ON employees.departmentid = departments.departmentid | |
GROUP BY | |
departments.departmentid | |
5. List employees that don't have a boss in the same department | |
SELECT | |
e.`name` | |
FROM | |
employees AS e | |
INNER JOIN employees AS b ON e.bossid = b.employeeid | |
WHERE | |
e.departmentid <> b.departmentid | |
6. List all departments along with the total salary there | |
SELECT | |
departments.`name`, | |
Sum(employees.salary) | |
FROM | |
departments | |
LEFT JOIN employees ON employees.departmentid = departments.departmentid | |
GROUP BY | |
departments.`name` | |
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