Created
November 11, 2014 11:50
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#include <stdio.h> | |
#include <string.h> | |
#include <algorithm> | |
#include <iostream> | |
#include <iterator> | |
using namespace std; | |
int abs(int x) { | |
return x > 0 ? x : -x; | |
} | |
int solution(int* A, int N) { | |
int left[N]; | |
int right[N]; | |
memset(left, 0, sizeof(int) * N); | |
memset(right, 0, sizeof(int) * N); | |
left[0] = A[0]; | |
for(int i = 1; i < N; ++i) { | |
if(A[i] > left[i - 1]) { | |
left[i] = A[i]; | |
} else { | |
left[i] = left[i - 1]; | |
} | |
} | |
// copy(left, left + N, ostream_iterator<int>(cout, "\t")); | |
// printf("\n"); | |
right[N - 1] = A[N - 1]; | |
for(int i = N - 2; i >= 0; --i) { | |
if(A[i] > right[i + 1]) { | |
right[i] = A[i]; | |
}else { | |
right[i] = right[i + 1]; | |
} | |
} | |
int max = 0; | |
for(int i = 0; i < N - 1; ++i) { | |
int cur = abs(left[i] - right[i + 1]); | |
if(cur > max) { | |
max = cur; | |
} | |
} | |
return max; | |
} | |
int main() { | |
int A[] = {1,3, -3 }; | |
int res = solution(A, sizeof(A)/sizeof(int)); | |
printf("%d\n", res); | |
int B[] = {4,3,2,5,1,1}; | |
res = solution(B, sizeof(B)/sizeof(int)); | |
printf("%d\n", res); | |
return 0; | |
} |
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