Current URL path via Twig in Drupal 8

myelement.html.twig

{#
/**
 * @file
 * Get the current URL path via Drupal 8 route name and twig function.
 */
#}
<a href="{{ url('<current>') }}">Current page</a>

If you use this in a block view, remember to turn off block caching in the "Advanced Settings"

Note that this returns the complete URL, not the path. If you just want the path, use

{{ path('<current>') }}

This works great, but what if I only need a specific parameter from the URL? For example, I want to style a portion of the Commerce checkout process if the user is on the Review page (mysite.com/checkout/388/review). How can I get just that final parameter (review)? When I use this code (

) in the file "commerce-checkout-form--with-sidebar.html.twig", I get the following output:

If I can get just "review" as that part of the class, I will be able to use CSS to style that area of the order review page.

Ah, I believe I have found the solution:

{% set url = url('')['#markup'] %}{{ url|split('/')|last }}

Ah, I believe I have found the solution:

{% set url = url('')['#markup'] %}{{ url|split('/')|last }}

Thanks, it works perfectly.

Nice, thanks for sharing!

Thanks, works well! For more URL path Twig tips in Drupal, see Functions in Twig templates.