Created
October 14, 2014 02:48
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Merge sort in Golang
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package main | |
import ( | |
"fmt" | |
) | |
func main() { | |
A := []int{3, 5, 1, 6, 1, 7, 2, 4, 5} | |
fmt.Println(sort(A)) | |
} | |
// top-down approach | |
func sort(A []int) []int { | |
if len(A) <= 1 { | |
return A | |
} | |
left, right := split(A) | |
left = sort(left) | |
right = sort(right) | |
return merge(left, right) | |
} | |
// split array into two | |
func split(A []int) ([]int, []int) { | |
return A[0:len(A) / 2], A[len(A) / 2:] | |
} | |
// assumes that A and B are sorted | |
func merge(A, B []int) []int { | |
arr := make([]int, len(A) + len(B)) | |
// index j for A, k for B | |
j, k := 0, 0 | |
for i := 0; i < len(arr); i++ { | |
// fix for index out of range without using sentinel | |
if j >= len(A) { | |
arr[i] = B[k] | |
k++ | |
continue | |
} else if k >= len(B) { | |
arr[i] = A[j] | |
j++ | |
continue | |
} | |
// default loop condition | |
if A[j] > B[k] { | |
arr[i] = B[k] | |
k++ | |
} else { | |
arr[i] = A[j] | |
j++ | |
} | |
} | |
return arr | |
} |
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