Created
October 11, 2016 14:02
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import time as t | |
import os as os | |
import sys as sys | |
def gerar_numero(a, b): | |
if a <= 0 and b > sys.maxsize - 2: | |
return gerar_numero(a, sys.maxsize - 2) | |
elif a >= 1 and b > sys.maxsize - 1: | |
return gerar_numero(a, sys.maxsize - 1) | |
else: | |
if a > b: | |
return gerar_numero(b, a) | |
elif a < 0: | |
return gerar_numero(0, b) - gerar_numero(0, abs(a)) | |
else: | |
tamanho_intervalo = b - a + 1 | |
tamanho_par = tamanho_intervalo % 2 == 0 | |
posicao_mediana = (tamanho_intervalo if tamanho_par else tamanho_intervalo + 1) / 2 | |
numero_mediana = b - posicao_mediana + (0 if tamanho_intervalo else 1) | |
return (a if gerar_boolean() else b) \ | |
if (b <= a + 1) \ | |
else (gerar_numero(a, numero_mediana) | |
if gerar_boolean() | |
else gerar_numero(numero_mediana, b)) | |
def gerar_boolean(): | |
b = get_ultimo(t.time()) % 2 == 0 | |
if b is True: | |
return True | |
else: | |
return False | |
def get_ultimo(arg): | |
s = str(arg) | |
r = 0 | |
for x in range(s.__len__()): | |
if s.__getitem__(x) is not '.': | |
r = int(s.__getitem__(x)) | |
return r | |
li = os.times().__getitem__(4) | |
for i in range(10): | |
gerar_numero(1, 1000) | |
print(str(os.times().__getitem__(4) - li) + " segundos") |
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