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/// Tour of Dart | |
/// A simple Mixin example about printer. | |
class Paper { | |
String sizeName = 'Paper'; | |
// bool printable = false; | |
// Paper(this.sizeName, this.printable); | |
/// Here we don't care whether Paper can be printed, |
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# Maintainer: Levente Polyak <anthraxx[at]archlinux[dot]org> | |
# Contributor: Giovanni Scafora <[email protected]> | |
# Contributor: Sarah Hay <[email protected]> | |
# Contributor: Martin Sandsmark <[email protected]> | |
pkgname=vlc | |
_vlcver=3.0.6 | |
# optional fixup version including hyphen | |
_vlcfixupver= | |
pkgver=${_vlcver}${_vlcfixupver//-/.r} |
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By default, when extracts the Xcode.zip, | |
macos will create tmp file in `/private/var/folders/v2/tbmrn60d2910x3w23ys5fgs00000gn/T/com.apple.AUHelperService`. | |
Sometimes, the /private has no ehough space to hold 19GB Xcode.app. | |
Thus we can create a soft link named `com.apple.AUHelperService` in the tmp dir. | |
Steps: | |
1. BACKUP `com.apple.AUHelperService` in `/private/var/folders/v2/tbmrn60d2910x3w23ys5fgs00000gn/T/` to `com.apple.AUHelperService_BACKUP` | |
2. mkdir named `com.apple.AUHelperService` wherever you have enough space, | |
3. ln -s /your/absolute/path/com.apple.AUHelperService /private/var/folders/v2/tbmrn60d2910x3w23ys5fgs00000gn/T | |
4. double click the Xcode.xip |
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" Plugin Manager | |
call plug#begin(expand('~/.vim/plugged')) | |
" 主题 | |
Plug 'arcticicestudio/nord-vim' | |
Plug 'tpope/vim-sensible' | |
Plug 'liuchengxu/space-vim-theme' | |
" 格式工具 | |
Plug 'Yggdroot/indentLine' " 缩进显示 | |
Plug 'scrooloose/nerdcommenter' " 注释工具 |
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tell application "System Events" | |
-- 前提/premiss: | |
-- 1. 在iCloud云盘下新建Bear文件夹/Create a new folder "Bear" under the iCloud | |
-- 脚本做的事:/What the script does: | |
-- 1. 自动化点击/Automated click | |
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#include <stdio.h> | |
#include <string.h> | |
#include <stdlib.h> | |
#include <time.h> | |
// 根据先序遍历判断是否是完全二叉树,输入-1表示null | |
struct TreeNode { | |
int ch; | |
struct TreeNode *left; | |
struct TreeNode *right; | |
}; |
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#include <bits/stdc++.h> | |
using namespace std; | |
const int maxn = 1e5+7; | |
std::vector<int> g[maxn], ans; | |
bool vis[maxn]; | |
int indeg[maxn]; | |
int n,m; | |
void toposort() | |
{ | |
queue<int> q; |
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#include <bits/stdc++.h> | |
using namespace std; | |
#define pass // | |
struct node | |
{ | |
node *lc, *rc; | |
int key, color,height; | |
node(){} | |
node(int key):key(key){} | |
}*root; |
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#include<bits/stdc++.h> | |
using namespace std; | |
const int maxn = 1000+7; | |
/* 二叉树的三种遍历方式:preorder, inorder, postorder | |
* 左子树T1, 右子树T2, 根 r | |
* 题意:给出preorder和inorder,求postorder | |
* 思想:先根据先序遍历和中序遍历建二叉树树,然后求后序遍历即可, 注意若只给出前序和后序则是无法建树的 | |
* 9 | |
1 2 4 7 3 5 8 9 6 | |
4 7 2 1 8 5 9 3 6 |
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// 1. 二叉树第i层最多2^{i-1}个节点 | |
// 2. 深度为k的二叉树最多右2^k-1个节点 | |
// 3. 对于二叉树,设节点数为n, 有n0 + n1 + n2 = n; (*1) | |
// n = B + 1; // B 为分支数目 | |
// n = n1 + 2*n2 + 1; (*2) | |
// 结合(*1)、(*2) 有 n0 = n2 + 1; (*3) | |
// 如用二叉链表表示,空指针数为n+1, 由(*3)、(*1)易得2*n0 + n1 = n + 1; | |
// 4. 具有n个节点的完全二叉树的深度为floor(log_2n)+1 | |
#include <bits/stdc++.h> |
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