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| # A solution to the CUCTF 2017 Future task using Z3Py | |
| # inspired by Hackeriet's solution in https://blog.hackeriet.no/solution-to-tuctf-2017-future/ | |
| from z3 import * | |
| # This is the flag format | |
| # flag = "TUCTF{..................}" | |
| auth = [0x8b, 0xce, 0xb0, 0x89, 0x7b, 0xb0, 0xb0, 0xee, 0xbf, 0x92, 0x65, 0x9d, 0x9a, 0x99, 0x99, 0x94, 0xad, 0xe4, 0x00] | |
| # Declare the variables for Z3 | |
| a, b, c, d, e, f, g, h, i, j, k, l, m = Ints('a b c d e f g h i j k l m') | |
| n, o, p, q, r, s, t, u, v, w, x, y, z = Ints('n o p q r s t u v w x y z') | |
| mat = [[a, b, c, d, e], [f, g, h, i, j], [k, l, m, n, o], [p, q, r, s, t], [u, v, w, x, y]] | |
| # Create a mapping dictionary based on genMatrix() | |
| mapper = {} | |
| for i in range(25): | |
| m = (i*2)%25 | |
| f = (i*7)%25 | |
| mapper[f] = mat[m/5][m%5] | |
| # Create the equations based on genAuthString() | |
| equations = [mat[0][0] + mat[4][4] == int(auth[0]), | |
| mat[2][1] + mat[0][2] == int(auth[1]), | |
| mat[4][2] + mat[4][1] == int(auth[2]), | |
| mat[1][3] + mat[3][1] == int(auth[3]), | |
| mat[3][4] + mat[1][2] == int(auth[4]), | |
| mat[1][0] + mat[2][3] == int(auth[5]), | |
| mat[2][4] + mat[2][0] == int(auth[6]), | |
| mat[3][3] + mat[3][2] + mat[0][3] == int(auth[7]), | |
| mat[0][4] + mat[4][0] + mat[0][1] == int(auth[8]), | |
| mat[3][3] + mat[2][0] == int(auth[9]), | |
| mat[4][0] + mat[1][2] == int(auth[10]), | |
| mat[0][4] + mat[4][1] == int(auth[11]), | |
| mat[0][3] + mat[0][2] == int(auth[12]), | |
| mat[3][0] + mat[2][0] == int(auth[13]), | |
| mat[1][4] + mat[1][2] == int(auth[14]), | |
| mat[4][3] + mat[2][3] == int(auth[15]), | |
| mat[2][2] + mat[0][2] == int(auth[16]), | |
| mat[1][1] + mat[4][1] == int(auth[17]), | |
| mat[0][0] == ord('T'), | |
| mat[2][1] == ord('U'), | |
| mat[4][2] == ord('C'), | |
| mat[1][3] == ord('T'), | |
| mat[3][4] == ord('F'), | |
| mat[1][0] == ord('{'), | |
| mat[2][4] == ord('}')] | |
| # Create a solver and solve | |
| s = Solver() | |
| s.add(equations) | |
| s.check() | |
| m = s.model() | |
| # Map the solved values to the flag | |
| solution = [m[mapper[ix]].as_long() for ix in range(25)] | |
| print(''.join(chr(int(i)) for i in solution)) |
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