FizzBuzz Python Solution

fizzBuzz.py

# Print the numbers from 1 to 100.
# But for multiples of three print “Fizz”
# and for multiples of five  print “Buzz”
#     For multiples of both  print “FizzBuzz”

for i in range(1,100) : 
    s = ''                      # Reset our string with every loop
    if i%3 == 0  :  s = 'Fizz'  # Test if it's got a Fizz
    if i%5 == 0  :  s = 'Buzz'  # Test if it's got a Buzz, too
    if   s == '' : s = i        # If it's still in its original state (no fizz, no buzz)
    print(s)                    # Then set it to the current number AND PRINT!
    
# I think there are two core takeaways from this exercise:
# (1) : Figure the most productive order to test for difference stances
#       Is one question better to ask BEFORE another?
# (2) : When trying to test if nothing's been done, 
#       The question "Is it still in its original state?" is sometimes better
#       than trying to throw the final test in an "else" clause.