-
-
Save MaskRay/4736618 to your computer and use it in GitHub Desktop.
给个数组,打乱了,比如:索引 0 1 2 3 4;值 3 2 1 4 0 。数组的值是下次跳的索引位置,这样的话数组有环,比如 0 -> 3 -> 4 -> 0 1 -> 2 -> 1, 求最长环的长度。
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
let huangBingchao a = | |
let n = Array.length a in | |
let rec go2 j i l = | |
if a.(i) < 0 then | |
(j, l) | |
else | |
let ii = a.(i) in | |
a.(i) <- j; | |
go2 (lnot i) ii (l+1) in | |
let rec go i mx = | |
if i < 0 then | |
mx | |
else | |
let (ix, l) = if a.(i) < 0 then (a.(i), 0) else go2 (-1) i 0 in | |
a.(i) <- lnot ix; | |
go (i-1) (max mx l) in | |
go (n-1) 0 | |
let read_int () = Scanf.scanf " %d" (fun x -> x) | |
let n = read_int() | |
let a = Array.init n (fun _ -> read_int());; | |
Printf.printf "%d\n" (huangBingchao a); |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment