Created
February 4, 2014 15:48
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MathProg: calculate mixed strategies Nash equilibrium (2 players, 0-sum game)
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data; | |
set P1S := a b c; | |
set P2S := 1 2 3 4; | |
param Payoff | |
: 1 2 3 4 := | |
a -5 3 1 8 | |
b 5 5 4 6 | |
c -4 6 0 5; | |
end; |
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set P1S; | |
set P2S; | |
param Payoff{P1S, P2S}; | |
var y{P1S} >= 0; | |
minimize GameValue: sum{i in P1S} y[i]; | |
s.t. Condition2{j in P2S}: | |
sum{i in P1S} Payoff[i,j] * y[i] >= 1; | |
solve; | |
printf "Value: %s\n", GameValue; | |
printf "Player 1 strategies:\n"; | |
for{i in P1S} | |
printf "Found %s, actual %s\n", y[i], y[i]/GameValue; | |
end; |
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set P1S; | |
set P2S; | |
param Payoff{P1S, P2S}; | |
var x{P2S} >= 0; | |
maximize GameValue: sum{j in P2S} x[j]; | |
s.t. Condition1{i in P1S}: | |
sum{j in P2S} Payoff[i,j] * x[j] <= 1; | |
solve; | |
printf "Value: %s\n", GameValue; | |
printf "Player 2 strategies:\n"; | |
for{j in P2S} | |
printf "Found %s, actual %s\n", x[j], x[j]/GameValue; | |
end; |
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