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Estimating the square of the mean, see www.mathiasfuchs.de/b2.html for the diary entry.
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# our sample size | |
n <- 10 | |
# generate all subsets of size 2 | |
co <- combn(n, 2) | |
# confirm that the false friend is biased by generating a lot of samples | |
f <- rep(0, 50000) | |
g <- rep(0, 50000) | |
for (k in 1:50000){ | |
if (k%%100==0) print(k) | |
s <- sample(6, n, replace=TRUE) | |
# the false friend | |
F <- mean(s)^2 | |
# the good friend | |
G <- mean(apply(co, 2, function(xx) prod(s[xx]))) | |
f[k] <- F | |
g[k] <- G | |
} | |
# confirm that the false friend is biased, and the good friend isn't, by checking that the false friend | |
print(t.test(f)) # doesn't contain the true value 12.25 | |
print(t.test(g)) # contains the true value 12.25 | |
# let's look at the particular example | |
s <- c(2, 2, 4, 6, 2, 6, 4, 5, 4, 6); | |
n <- length(s) | |
G <- mean(apply(combn(n, 2), 2, function(xx) prod(s[xx]))) | |
H <- mean(apply(combn(n, 4), 2, function(xx) prod(s[xx]))) | |
K <- G^2 - H | |
t <- qt(1-0.05/2, df = n-1) | |
print(paste(sep="", "[", G - t * sqrt(K), ", ", G + t * sqrt(K), "]")) | |
# what happens on a larger sample size? | |
n <- 200 | |
s <- sample(6, n, replace=TRUE) | |
G <- mean(apply(combn(n, 2), 2, function(xx) prod(s[xx]))) | |
H <- mean(apply(combn(n, 4), 2, function(xx) prod(s[xx]))) | |
K <- G^2 - H | |
t <- qt(1-0.05/2, df = n-1) | |
print(paste(sep="", "[", G - t * sqrt(K), ", ", G + t * sqrt(K), "]")) |
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