3.3 Write a program to prompt for a score between 0.0 and 1.0. If the score is out of range, print an error. If the score is between 0.0 and 1.0, print a grade using the following table: Score Grade >= 0.9 A >= 0.8 B >= 0.7 C >= 0.6 D < 0.6 F If the user enters a value out of range, print a suitable error message and exit. For the test, enter a …

py4e_ex_03_03

score = input("Enter Score: ")

x = float(score)

if x >=0.9:
    print("A")
elif x >=0.8:
    print("B")
elif x >=0.7:
    print("C")
elif x >=0.6:
    print("D")
elif x <0.6:
    print("F")
else: print("error")

doesn`t work if I use 2.0
no "error" message

doesn`t work if I use 2.0 no "error" message

check your code

doesn`t work if I use 2.0 no "error" message

check your code

I`ve copied it to to a new file and result is the same - no "error" message

doesn`t work if I use 2.0 no "error" message

check your code

why even comment?

doesn`t work if I use 2.0 no "error" message

check your code

I`ve copied it to to a new file and result is the same - no "error" message

i added an if statement, if score > 1.0, print('error')

doesn`t work if I use 2.0 no "error" message

check your code

I`ve copied it to to a new file and result is the same - no "error" message

You need to define the range of acceptable scores before before specifying the grades.
Here is my code that works well for values below 0 and above 1.

Receive input from user and convert to float

inp = input("Enter Score: ")
score = float (inp)

Define boundary of scores

if score > 1:
print ('Only numbers less than 1 and bigger than O are allowed')
elif score < 0:
print ('student cannot have a negative score')

Give suitable results

elif score >= 0.9:
print ('A')
elif score >= 0.8:
print ('B')
elif score >= 0.7:
print ('C')
elif score >= 0.6:
print ('D')
elif score < 0.6:
print ('F')

Hope it helps!

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On May 11, 2022, at 9:03 AM, chika691 ***@***.***> wrote: ***@***.*** commented on this gist. doesn`t work if I use 2.0 no "error" message check your code I`ve copied it to to a new file and result is the same - no "error" message You need to define the range of acceptable scores before before specifying the grades. Here is my code that works well for values below 0 and above 1. Receive input from user and convert to float inp = input("Enter Score: ") score = float (inp) Define boundary of scores if score > 1: print ('Only numbers less than 1 and bigger than O are allowed') elif score < 0: print ('student cannot have a negative score') Give suitable results elif score >= 0.9: print ('A') elif score >= 0.8: print ('B') elif score >= 0.7: print ('C') elif score >= 0.6: print ('D') elif score < 0.6: print ('F') Hope it helps! — Reply to this email directly, view it on GitHub, or unsubscribe. You are receiving this because you commented.