Flip X number of coins and then count them. Or flip 0 number of coins and count forever.

CoinBot.py

#!/env/Python3.10.4
#/MobCat (2022)

import random
from datetime import datetime


heads = 0
tails = 0
total = 0


number = input("Number of times to flip coin: ")
start  = datetime.now()

try:
	if int(number) == 0:
		while True:
			flip = random.randint(0, 1)
			if (flip == 0):
				heads += 1
			else:
				tails += 1
			total += 1

			quotient = heads/total
			percent = quotient * 100

			quotient2 = tails/total
			percent2 = quotient2 * 100

			print(f"total={total} heads={heads}({str(round(percent, 2))}%) tails={tails}({str(round(percent2, 2))}%) runtime={datetime.now()-start}  ", end='\r')
	else:
		for i in range(int(number)):
			flip = random.randint(0, 1)
			if (flip == 0):
				heads += 1
			else:
				tails += 1
			total += 1

			quotient = heads/total
			percent = quotient * 100

			quotient2 = tails/total
			percent2 = quotient2 * 100

			print(f"total={total} heads={heads}({str(round(percent, 2))}%) tails={tails}({str(round(percent2, 2))}%) runtime={datetime.now()-start}  ", end='\r')

	print("\ndone.")

except KeyboardInterrupt:
	print("\nScript terminated by user.")