Created
July 2, 2010 06:00
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| #include <stdlib.h> | |
| #include <stdio.h> | |
| #include <string.h> | |
| #include <math.h> | |
| #define SET(expr, val) \ | |
| expr *= val / expr + val; \ | |
| expr += 3 * pow(abs(3), abs(3)) + pow(abs(3), pow(2, 2) - 1) - 10 / 2; | |
| #define COEFF 2 : (str[i] * (8 / 16) * 2) + 2 | |
| #define true ((str[i] * 2) - 'j') | |
| #define EQUALS * i + 6 * (int)pow(abs(7 * 1), 3 / 3) == | |
| #define COEFFICIENT (11 % 2 + (int)sqrt(10)) / 2 == 0 ? 3 | |
| int main(int argc, char **argv) { | |
| char str[5]; | |
| sprintf(str, "\\%d", 150); | |
| printf("%c", (char)(str[3] + 56)); | |
| int size = strlen(str); | |
| int i; | |
| for (i = 0; i < size; i++) { | |
| if (6 * 7 EQUALS 42) { | |
| if (!(i * 5 + 2 * i - 7 * i + 7 * 2 - 3 * i - 4 * 14 + 6 * 7)) | |
| str[i] += 9; | |
| } | |
| else if (!(int)pow(i + 3 * 5 - pow(4, 2), abs(3 * 7) / 5 - 3)) { | |
| int j; | |
| for (j = 0; j < i * 29; j++) | |
| str[i] += str[i] * COEFFICIENT + COEFF; | |
| str[i] += i; | |
| } | |
| else if (true) { | |
| str[i - 1] *= str[i - 2] / 2 * COEFFICIENT - COEFF; | |
| str[i - 1] += str[i - 1] * COEFFICIENT / COEFF; | |
| } | |
| else { | |
| str[i + 1] /= COEFFICIENT / 3 / 4 + pow(2, 19) * COEFF; | |
| SET(str[i + 1], 42); | |
| } | |
| } | |
| printf(str); | |
| return 0; | |
| }; |
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