Created
June 4, 2024 05:51
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def levenshtein(chaine1, chaine2): | |
n = len(chaine1) | |
m = len(chaine2) | |
d = [[0 for j in range(m + 1)] for i in range(n + 1)] | |
for i in range(0, n + 1): | |
d[i][0] = i | |
for j in range(0, m + 1): | |
d[0][j] = j | |
for i in range(0, n): | |
for j in range(0, m): | |
if chaine1[i] == chaine2[j]: | |
cout_sub = 0 | |
else: | |
cout_sub = 1 | |
d[i + 1][j + 1] = min( | |
d[i][j + 1] + 1, | |
d[i + 1][j] + 1, | |
d[i][j] + cout_sub, | |
) | |
return d[n][m] |
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