Order an array of objects based on another array order

order.js

/**
 * Sort array of objects based on another array
 */

const mapOrder = (array: any, order: any, key: any) => {
  array.sort((a: any, b: any) => {
    const A = a[key];
    const B = b[key];
    return order.indexOf(A) > order.indexOf(B) ? 1 : -1;
  });
  return array;
};


/**
 * Example:
 */

var item_array, item_order, ordered_array, item_order_2, item_order_3;

item_array = [ 
  { id: 2, label: 'Two', se: { new: false }  }
, { id: 3, label: 'Three', se: { new: false } }
, { id: 5, label: 'Five', se: { new: false } }
, { id: 4, label: 'Four', se: { new: false } }
, { id: 1, label: 'One', se: { new: true } }
];

item_order = [1, 2, 3, 4, 5];
item_order_2 = ['Five', 'Four', 'Three', 'Two', 'One'];
item_order_3 = [true, false];

ordered_array = mapOrder(item_array, item_order_2, 'label');

console.log('Ordered:', JSON.stringify(ordered_array));