Shell script to deploy a Lambda function

deploy-lamba.sh

#!/usr/bin/env bash

deploy-lambda $1

# A little shell script I worked up to deploy Lambda functions from my local dev box
function deploy-lambda {
  basedir=$HOME/work
  dir=$1
  role=${LAMBDA_ROLE:-arn:aws:iam::123456789012:role/default-role-goes-here}
  runtime=${LAMBDA_RUNTIME:-provided}
  
  if [ ! $dir ] ; then
    if [[ ! $PWD =~ $HOME/work/ ]] ; then
      echo "You must call package_lambda from a directory under $HOME/work or with an argument"
      return 1;
    fi
    dir=$PWD;
  else
    dir="$basedir/$dir"
  fi

  if [ ! -d $dir ] ; then
    echo "No such directory \"$dir\""
    return 1;
  fi

  function_name=${FUNCTION_NAME:-`basename $dir`}
  function_exists=`aws lambda get-function --function-name $function_name 2> /dev/null`
  if [ ! "$function_exists" ] ; then
    echo "Creating Lambda function $function_name"
    # I'm using this to do Lambda functions in Perl, which require a custom runtime. Take out the two lines below 
    # if you don't need custom layers
    layer_name=my_custom_runtime
    layer=${LAMBDA_LAYER:-`aws lambda list-layer-versions --layer-name $layer_name --region us-east-1 --query 'LayerVersions[0].LayerVersionArn'`}
    
    awscmd="aws lambda create-function --function-name $function_name --handler handler.handle \
      --role $LAMBDA_ROLE --runtime provided --layers $layer --zip-file fileb://$basedir/$function_name.zip"
  else
    echo "Updating Lambda function $function_name"
    awscmd="aws lambda update-function-code --function-name $function_name --zip-file fileb://$basedir/$function_name.zip"
  fi
  
  # OK, this is still pretty perl specific. I'll fix that later maybe
  zipcmd="zip -r $basedir/$function_name.zip handler.pl local"
  cd $dir
  echo "$zipcmd && $awscmd"
  if sh -c "$zipcmd && $awscmd" ; then
    rv=0
  else
    rv=-1
  fi
  cd $OLDPWD
  return $rv
}