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October 7, 2025 15:18
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Toy RSA implementation (Understanding Cryptography, Second Edition, pp. 206-208)
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#!/usr/bin/env python3 | |
import math, random | |
# RSA Key Generation, p. 208 | |
p = int(input('p? ')) | |
q = int(input('q? ')) | |
n = p * q | |
phi = (p - 1) * (q - 1) | |
e = random.choice([e for e in range(1, phi) if math.gcd(e, phi) == 1]) | |
d = next(iter([d for d in range(1, phi) if ((d *e ) % phi) == 1])) | |
k_pub = (n, e) | |
k_pr = d | |
print(f'{k_pub = }, {k_pr = }') | |
# RSA Encryption (7.1), p. 206 | |
x = int(input('x? ')) | |
y = (x ** e) % n | |
print(f'{y = }') | |
# RSA Decryption (7.2), p. 207 | |
print(f'({y} ** {d}) % {n} = {(y ** d) % n}') |
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