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/* selection problem solution in C*/ | |
#include<stdio.h> | |
/*swap two elements*/ | |
void swap(int *a,int *b) | |
{ | |
int temp; | |
temp = *a; | |
*a = *b; | |
*b = temp; | |
} | |
/* recursivley partition the sub-arrays */ | |
int select(int A[], int iBegin, int iEnd, int I) | |
{ | |
int iPivot; // pivot index | |
if (iBegin < iEnd) | |
{ | |
iPivot = partition(A, iBegin, iEnd); | |
int k = iPivot - iBegin +1; | |
//k is number of elements in left side of partition, plus one for pivot element | |
if(I == k) | |
return A[iPivot];//check if it is ith smallest | |
// if ith min occurs in the left sub-array | |
else if(I < k) | |
return select(A, iBegin, iPivot-1, I); | |
// if ith min occurs in the right sub-array | |
else | |
return select(A, iPivot+1, iEnd, I-k); | |
} | |
} | |
/* | |
Takes last element in the array as pivot and reorder such that | |
smaller values to its left and larger or equal values to its right | |
iBegin : Beginn index | |
iEnd : End index | |
*/ | |
int partition(int A[], int iBegin, int iEnd) | |
{ | |
int pivotValue = A[iEnd]; | |
int storeIndex = iBegin; | |
int i; | |
for (i = iBegin; i < iEnd; ++i) | |
{ | |
if(A[i] < pivotValue) | |
{ | |
swap(&A[i], &A[storeIndex]); | |
storeIndex++; | |
} | |
} | |
swap(&A[iEnd], &A[storeIndex]); | |
return storeIndex; | |
} | |
int main() | |
{ | |
int T,N,I; | |
int A[200]; | |
int i,j; | |
scanf("%d",&T); | |
for(i=0; i<T; i++) | |
{ | |
scanf("%d",&N); | |
for(j=0; j<N; j++) | |
{ | |
scanf("%d",&A[j]); | |
} | |
scanf("%d",&I); | |
printf("%d\n",select(A,0,N-1,I)); | |
} | |
return 0; | |
} |
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