Created
July 19, 2020 07:22
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/* | |
Sort-of brute force... I know there's a cleverer way to | |
do this with XORs and bit tricks but if the answer doesn't | |
fit into 53-bit int I'd be hosed so I'm sticking to what | |
I know will work =P | |
O(max(a.length, b.length)) | |
*/ | |
var addBinary = function(a, b) { | |
const result = []; | |
const len = Math.max(a.length, b.length); | |
let i = 1; | |
let carry = 0; | |
while(len - i >= 0){ | |
const x = a[a.length-i] === '1' ? 1 : 0; | |
const y = b[b.length-i] === '1' ? 1 : 0; | |
const sum = x + y + carry; | |
if(sum === 0){ | |
result.push(0); | |
carry = 0; | |
} | |
else if(sum === 1){ | |
result.push(1); | |
carry = 0; | |
} | |
else if(sum === 2){ | |
result.push(0); | |
carry = 1; | |
} | |
else if(sum === 3){ | |
result.push(1); | |
carry = 1; | |
} | |
i++; | |
} | |
if(carry) result.push(1); | |
return result.reverse().join(''); | |
}; |
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