Radcliffe · January 13, 2017 00:02 · Radcliffe · Sep 11, 2021 · TonyHoldroyd · Sep 11, 2021
diff --git a/cryptarithm-solver.py b/cryptarithm-solver.py
 #!/usr/bin/env python

 # This programs solves additive cryptarithms using brute force.

 # Example: solve_cryptarithm(['SEND', 'MORE', 'MONEY']) returns a list of
 # all solutions to the equation SEND + MORE = MONEY, where each letter 
 # stands for a different digit in base 10. Leading zeros are not allowed.


 from itertools import permutations
 import sys

 def word_to_number(word, lookup):
    """Convert a word to a number by replacing each letter with a digit, using a lookup dictionary."""
    return int(''.join(str(lookup[letter]) for letter in word))

 def solve_cryptarithm(words):
    """Solve an equation like SEND + MORE = MONEY given a list of three or more words.
       The last word should be the sum of the other words."""
    words = [word.upper() for word in words]
    letters = list(set(''.join(words)))
    if len(letters) > 10:
        print('Too many distinct letters (%d).' % len(letters))
        return

    for perm in permutations(range(10), len(letters)):
        lookup = dict(zip(letters, perm))
        if all(lookup[w[0]] > 0 for w in words):
            numbers = [word_to_number(w, lookup) for w in words]
            if sum(numbers[:-1]) == numbers[-1]:
                yield numbers

 if __name__ == '__main__':
    if len(sys.argv) < 4:
        print('At least three arguments required.')
    else:
        for solution in solve_cryptarithm(sys.argv[1:]):
            print (' + '.join(str(n) for n in solution[:-1]) + ' = ' + str(solution[-1]))
	#!/usr/bin/env python

	# This programs solves additive cryptarithms using brute force.

	# Example: solve_cryptarithm(['SEND', 'MORE', 'MONEY']) returns a list of
	# all solutions to the equation SEND + MORE = MONEY, where each letter
	# stands for a different digit in base 10. Leading zeros are not allowed.


	from itertools import permutations
	import sys

	def word_to_number(word, lookup):
	"""Convert a word to a number by replacing each letter with a digit, using a lookup dictionary."""
	return int(''.join(str(lookup[letter]) for letter in word))

	def solve_cryptarithm(words):
	"""Solve an equation like SEND + MORE = MONEY given a list of three or more words.
	The last word should be the sum of the other words."""
	words = [word.upper() for word in words]
	letters = list(set(''.join(words)))
	if len(letters) > 10:
	print('Too many distinct letters (%d).' % len(letters))
	return

	for perm in permutations(range(10), len(letters)):
	lookup = dict(zip(letters, perm))
	if all(lookup[w[0]] > 0 for w in words):
	numbers = [word_to_number(w, lookup) for w in words]
	if sum(numbers[:-1]) == numbers[-1]:
	yield numbers

	if __name__ == '__main__':
	if len(sys.argv) < 4:
	print('At least three arguments required.')
	else:
	for solution in solve_cryptarithm(sys.argv[1:]):
	print (' + '.join(str(n) for n in solution[:-1]) + ' = ' + str(solution[-1]))