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Simple TypeScript pattern matching
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const t1 = match(2) (_ => [ | |
[ | |
Number, | |
_ => 'number!' | |
], | |
[ | |
_ > 3, | |
_ => _ + 3 | |
], | |
[ | |
_ == 2, | |
_ => `asdasd${_}`, | |
], | |
]); | |
// t1 is 'number!' | |
const t2 = match('2') (_ => [ | |
[ | |
Number, | |
_ => console.log('number!') | |
], | |
[ | |
String, | |
_ => console.log('string!') | |
], | |
[ | |
Boolean, | |
_ => console.log('boolean!') | |
], | |
]); | |
// t2 is undefined, logged 'string!' |
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export type Matcher<T> = T extends Array<any> ? [ | |
boolean | Function | T, | |
(...args: T) => any | |
] : [ | |
boolean | Function | T, | |
(arg: T) => any | |
]; | |
export type Match<T = any, M extends Matcher<T>[] = Matcher<T>[]> = (_: T) => M; | |
export const match = <T>(thing: T) => <M extends Match<T>>(f: M): ReturnType<ReturnType<M>[number][1]> => { | |
const res = f(thing); | |
for (const n of res) { | |
const _ = () => n[1](thing); | |
const success = (false | |
|| n[0] === thing | |
|| n[0] === true | |
|| (typeof n[0] === 'function' && ((typeof thing === 'object' && thing instanceof n[0]) || Object(thing) instanceof n[0])) | |
|| (Array.isArray(n[0]) && Array.isArray(thing) && n[0].length === thing.length && thing.every((_, i) => _ === n[0][i])) | |
|| (typeof n[0] === 'object' && (thing === n[0] || Object.keys(n[0]).every(key => n[0][key] === thing[key]))) | |
); | |
if (success) { | |
return _(); | |
} | |
} | |
} |
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