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Kth largest array element without array sort method, using min heap
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example:- | |
input: | |
array size=5 | |
kth =3 | |
arr[]={9 12 2 15 2} | |
output: | |
9 | |
import java.util.*; | |
import java.lang.*; | |
import java.io.*; | |
/* Name of the class has to be "Main" only if the class is public. */ | |
class Ideone | |
{ | |
public static void main (String[] args) throws java.lang.Exception | |
{ | |
Scanner sc=new Scanner(System.in); | |
int size=sc.nextInt(); | |
int k=sc.nextInt(); | |
int[] arr=new int[size]; | |
for(int i=0;i<size;i++){ | |
arr[i]=sc.nextInt(); | |
} | |
PriorityQueue<Integer> minhip=new PriorityQueue<>(); | |
for(int i:arr){ | |
if(!minhip.contains(i)){ | |
minhip.add(i); | |
} | |
if(minhip.size()>k){ | |
minhip.remove(); | |
} | |
} | |
System.out.println(minhip.remove()); | |
} | |
} |
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