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June 12, 2018 23:18
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CodeBuddy Week5
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a=input().split() | |
k=int(input()) | |
for i in range(len(a)): | |
a[i]=int(a[i]) | |
#a=[-5,-30,20,17,14,-7,-4,-9,11,20,23,42,-38,39,32,-8,-22,-50,-37] | |
ans=[] | |
a.sort() | |
tmin=[10000,-1,-1,-1] | |
for t in range(len(a)): | |
i=0 | |
j=len(a)-1 | |
while(i!=j): | |
if(i==t): | |
i+=1 | |
continue | |
elif(j==t): | |
j-=1 | |
continue | |
if(abs(a[t]+a[i]+a[j]-k)<tmin[0]): | |
tmin=[abs(a[t]+a[i]+a[j]-k),a[t],a[i],a[j]] | |
if((a[t]+a[i]+a[j]-k)<0): | |
i+=1 | |
else: | |
j-=1 | |
tmin[0]=tmin[1]+tmin[2]+tmin[3] | |
print(tmin[0]) |
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#Greedy Approach - O(n), objF is the objective function value | |
#Keep choosing the jump value which gets you the furthest | |
def solution(arr): | |
n=len(arr) | |
objF=[arr[0],arr[0]] | |
count=1 | |
for i in range(1,n): | |
objF[0]=max(objF[0],i+arr[i]) | |
objF[1] -= 1 | |
if (i==n-1): | |
return count | |
if (objF[1]==0): | |
objF[1]=objF[0]-i; | |
count+=1 | |
if(i>=objF[0]): | |
return "Not Possible" | |
return "Not Possible" | |
a=input().split() | |
for i in range(len(a)): | |
a[i]=int(a[i]) | |
print(solution(a)) |
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