How to open a link through a tkinter button in Python

ButtonToBrowser

#---------------------------------
# Random Resource Web ©
# Randomresourceweb.blogspot.com
#---------------------------------

from tkinter import *
import webbrowser

root = Tk()

new = 1
url = "https://www.google.com"

def openweb():
    webbrowser.open(url,new=new)

Btn = Button(root, text = "This opens Google",command=openweb)
Btn.pack()

root.mainloop()

It appears to be blank tho.

It appears to be blank tho.

Hey, I just re-ran this code and it should definitely be working!

its working

Indeed, its working with Python3 and also with from Tkinter import * at line 6 wih Python2. Maybe you have some utf8 coding problems with that copyright sign.

is there a way to put a box to type a link I want it to go too

is there a way to put a box to type a link I want it to go too

Hi, yea

1. Add this piece of code after the openweb function (All it does it add an entry widget so you can enter a line of text)
   link = Entry(root)
link.pack()
2. And then replace url in the openweb function to link.get() (Which gets the value of the entry widget instead of the hard-coded url)
   Hope this helped!

This is awesome! Thanks! You got a star.

Thank you <3

This is what I wanted. Thanks mate....

Me sirvió para mi proyecto muchas gracias!

Thank you !

can you guys try the same with custom tkinter? it doesn't seem to work as i intended

is there a way to add this with radio buttons, like if optionA is selected it opens linkA... ect ect?

@ldrak20 Well yes, the important part is the use of webbrowser.open function. You can call it from wherever you'd like.