Compare and find anagrams in an array of strings

maxAnagrams.ts

const wordsAreAnagrams = (a: string, b: string) =>
  a.split("").sort().join("") === b.split("").sort().join("")

const findAnagram = (word: string, compareList: string[]) => {
  let result = null
  compareList.every((w: string) => {
    if (wordsAreAnagrams(word, w)) {
      result = w
      return false
    }
    return true
  })
  return result
}

const getAnagramCounts = (list: string[]) =>
  list.reduce(
    (
      agg: {
        [key: string]: number
      },
      incoming: string
    ) => {
      const currentBaseWords = Object.keys(agg)
      const word = incoming.toLowerCase()
      const anagramCountExists = findAnagram(word, currentBaseWords)

      return anagramCountExists
        ? {
            ...agg,
            [anagramCountExists]: agg[anagramCountExists] + 1,
          }
        : { ...agg, [word]: 0 }
    },
    {}
  )

const maxAnagrams = (list: string[]) => {
  const anagramCount = getAnagramCounts(list)
  const highestAnagramWord = Object.entries(anagramCount).sort((a, b) =>
    a[1] < b[1] ? 1 : -1
  )

  return highestAnagramWord[0] && highestAnagramWord[0][0]
    ? highestAnagramWord[0][0]
    : ""
}

console.assert(maxAnagrams(["his", "tokyo", "sih", "Kyoto", "ish"]) === "his")
console.assert(
  maxAnagrams([
    "abets",
    "taser",
    "baste",
    "aster",
    "stare brake",
    "tears break",
    "baker rates",
  ]) === "stare brake"
)

console.info("All assertions passed")