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Swap Nodes in Pairs
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Given a linked list, swap every two adjacent nodes and return its head. | |
For example, | |
Given 1->2->3->4, you should return the list as 2->1->4->3. | |
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed. | |
/** | |
* Definition for singly-linked list. | |
* public class ListNode { | |
* int val; | |
* ListNode next; | |
* ListNode(int x) { | |
* val = x; | |
* next = null; | |
* } | |
* } | |
*/ | |
public class Solution { | |
public ListNode swapPairs(ListNode head) { | |
// Start typing your Java solution below | |
// DO NOT write main() function | |
if (head==null) return head; | |
ListNode helper=new ListNode(0); | |
helper.next=head; | |
ListNode n1=helper; | |
ListNode n2=head; | |
while(n2!=null&& n2.next!=null){ | |
n1.next=n2.next; | |
n2.next=n2.next.next; | |
n1.next.next=n2; | |
n1=n2; | |
n2=n2.next; | |
} | |
return helper.next; | |
} | |
} |
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