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Search Insert Position
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Given a sorted array and a target value, return the index if the target is found. If not, | |
return the index where it would be if it were inserted in order. | |
You may assume no duplicates in the array. | |
Here are few examples. | |
[1,3,5,6], 5 → 2 | |
[1,3,5,6], 2 → 1 | |
[1,3,5,6], 7 → 4 | |
[1,3,5,6], 0 → 0 | |
Time Complexity: O(lgn) | |
public class Solution { | |
public int searchInsert(int[] A, int target) { | |
// Start typing your Java solution below | |
// DO NOT write main() function | |
if (A==null||0==A.length) return 0; | |
int start=0; | |
int end=A.length-1; | |
while (start<=end){ | |
int mid=(start+end)/2; | |
if (A[mid]==target){ | |
return mid; | |
} | |
else if (A[mid]>target){ | |
end=mid-1; | |
} | |
else{ | |
start=mid+1; | |
} | |
} | |
return start; | |
} | |
} |
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