gistfile1.txt

a=0
b=0
c=0
d=0
e=0
f=0
t=0

for i0 in range(5):
    a += 1
    for i1 in range(5):
        b += 1
        for i2 in range(5):
            c += 1
            for i3 in range(5):
                d += 1
                for i4 in range(5):
                    e += 1
                    print("a=" + str(a) + " b=" + str(b) + " c=" + str(c) + " d=" + str(d) + " e=" + str(e))
                    if a==b or a==c or a==d or a==e or b==c or c==d or d==e:
                        f += 1
                    else:
                        t += 1
                e = 0
            d = 0
            e = 0
        c = 0
        d = 0
        e = 0
    b = 0
    c = 0
    d = 0
    e = 0

print("t=" + str(t) + " f=" + str(f))
print("전체 경우의 수: " + str(t+f) + "\n조건과 일치하는 경우의 수: " + str(t))
print("답: " + str(t))

IJustWantedToPlayMinecraft.py

a=0
b=0
c=0
d=0
e=0
f=0
t=0

for i0 in range(5):
    a += 1
    for i1 in range(5):
        b += 1
        for i2 in range(5):
            c += 1
            for i3 in range(5):
                d += 1
                for i4 in range(5):
                    e += 1
                    print("a=" + str(a) + " b=" + str(b) + " c=" + str(c) + " d=" + str(d) + " e=" + str(e))
                    if a==b or a==c or a==d or a==e or b==c or c==d or d==e:
                        f += 1
                    else:
                        t += 1
                e = 0
            d = 0
            e = 0
        c = 0
        d = 0
        e = 0
    b = 0
    c = 0
    d = 0
    e = 0

print("t=" + str(t) + " f=" + str(f))
print("전체 경우의 수: " + str(t+f) + "\n조건과 일치하는 경우의 수: " + str(t))
print("답: " + str(t))

속도가 느리니 C++로 다시 짜 봅시다

#include <iostream>
using namespace std;
int main(){
int a = 0;
int b = 0;
int c = 0;
int d = 0;
int e = 0;
int f = 0;
int t = 0;

for (int i0=0; i0<5; i0++){
a += 1;
for (int i1=0; i1<5; i1++){
b += 1;
for (int i2=0; i2<5; i2++){
c += 1;
for (int i3=0; i3<5; i3++){
d += 1;
for (int i4=0; i4<5; i4++){
e += 1;
cout << "a=" << a << " b=" << b << " c=" << c << " d=" << d << " e=" << e << endl;
if (a==b or a==c or a==d or a==e or b==c or c==d or d==e){
f += 1;
}
else {
t += 1;
}
};
e = 0;
};
d = 0;
e = 0;
};
c = 0;
d = 0;
e = 0;
};
b = 0;
c = 0;
d = 0;
e = 0;
};

cout << "t=" << t << " f=" << f << endl;
cout << "전체 경우의 수: " << t+f << "\n조건과 일치하는 경우의 수: " << t << endl;
cout << "답: " << t << endl;
return 0;
};

짜왔습니다.