Created
July 20, 2022 00:59
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An example of using threads to generate a fractal
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import java.awt.Color; | |
import java.awt.image.BufferedImage; | |
import java.io.File; | |
import java.io.IOException; | |
import java.util.ArrayList; | |
import java.util.List; | |
import java.util.concurrent.Callable; | |
import java.util.concurrent.ExecutionException; | |
import java.util.concurrent.ExecutorService; | |
import java.util.concurrent.Executors; | |
import java.util.concurrent.Future; | |
import java.util.logging.Level; | |
import java.util.logging.Logger; | |
import javax.imageio.ImageIO; | |
public class ThreadedFractal { | |
public static void main(String[] args) throws InterruptedException { | |
int k = 19000; | |
BufferedImage image = new BufferedImage(k, k, BufferedImage.TYPE_INT_RGB); | |
int threadWorking = 0; | |
int nbProc = Runtime.getRuntime().availableProcessors(); | |
ExecutorService service = Executors.newFixedThreadPool(nbProc); | |
List<FractalCallable> tasks = new ArrayList<>(nbProc); | |
for (int i = 0; i < nbProc; i++) { | |
//new MandelbrotImage(k*k*i/nbProc,k*k*(i+1)/nbProc,k); | |
int a = (int) ((k * k * (long) i) / nbProc); | |
int b = (int) ((k * k * ((long) i + 1)) / nbProc); | |
tasks.add(new FractalCallable( | |
i, | |
image, | |
a, | |
b, | |
k | |
)); | |
} | |
System.out.println("Now building..." + tasks.size()); | |
List<Future<Void>> results = service.invokeAll(tasks); | |
System.out.println("Done processing" + results.size()); | |
try { | |
for (Future<Void> result : results) { | |
result.get(); | |
} | |
System.out.println("Writing images"); | |
ImageIO.write(image, "png", new File("Test.png")); | |
} catch (ExecutionException ex) { | |
Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); | |
} catch (IOException ex) { | |
Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); | |
} | |
service.shutdownNow(); | |
System.out.println("All done"); | |
} | |
public static class FractalCallable implements Callable<Void> { | |
private int count; | |
private BufferedImage image; | |
private int a, b, k; | |
public FractalCallable(int count, BufferedImage image, int a, int b, int k) { | |
this.count = count; | |
this.image = image; | |
this.a = a; | |
this.b = b; | |
this.k = k; | |
} | |
@Override | |
public Void call() throws Exception { | |
int x = 0; | |
int y = 0; | |
try { | |
for (int u = a; u < b; u++) { | |
x = u % k; | |
y = u / k; | |
image.setRGB( | |
x, | |
y, | |
function(((u % k) / (k / 2.0)) - 1.5, | |
(u / (k * k / 2.0)) - 1, | |
1)); | |
} | |
System.out.println("Completed " + count); | |
} catch (Exception exp) { | |
System.out.println(count + "Failed to write to " + x + "x" + y); | |
System.out.println("Started " + count + "; a = " + a + "; b = " + b + "; k = " + k); | |
throw exp; | |
} | |
return null; | |
} | |
public int function(double real, double imag, int accuracy) { | |
int max; | |
double p = (real - 0.25) * (real - 0.25) + imag * imag; | |
if ((real + 1) * (real + 1) + imag * imag < 1d / 16d || real < Math.sqrt(p) - 2 * p + 0.25) { | |
max = 0; | |
} else { | |
double a = 0, b = 0, temp; | |
max = 1024 * accuracy; | |
while (max > 0 && a * a + b * b < 4) { | |
temp = a; | |
a = a * a - b * b + real; | |
b = 2 * temp * b + imag; | |
max--; | |
} | |
} | |
max = (1024 * accuracy - max) / accuracy; | |
return (max == 1024 ? Color.BLACK : new Color(max < 256 ? 255 : (max < 512 ? 511 - max : 0), max < 256 ? max : (max < 768 ? 255 : 1023 - max), max < 512 ? 0 : (max < 768 ? max - 512 : 255))).getRGB(); | |
} | |
} | |
} |
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This is "a" answer to https://stackoverflow.com/questions/73044685/problem-with-multi-thread-rendering-of-a-fractal#73044685 ... before it was closed