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Sorting an array by an object property
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// Swift 3 | |
// Simple object example | |
class Phone { | |
let name: String | |
let serialNumber: Int | |
init(name: String, serialNumber: Int) { | |
self.name = name | |
self.serialNumber = serialNumber | |
} | |
} | |
// Create objects | |
let phoneOne = Phone(name: "Cell", serialNumber: 12345) | |
let phoneTwo = Phone(name: "Work", serialNumber: 24586) | |
let phoneThree = Phone(name: "Test Phone", serialNumber: 56893) | |
// Create array of Phones | |
var myPhones: [Phone] = [phoneOne, phoneTwo, phoneThree] | |
// Example 1: Sort array in-place by name in ASCENDING alphabetical order | |
// myPhones is now in this order: [phoneOne, phoneThree, phoneTwo] | |
myPhones.sort(by: { $0.name < $1.name }) | |
// Example 2: Sort into a new array by serial number in DECENDING order | |
// newSortedArray is now in this order: [phoneThree, phoneTwo, phoneOne] | |
let newSortedArray = myPhones.sorted(by: { $0.serialNumber > $1.serialNumber}) | |
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