Parsing URL Code - Cause why not?

url_parse.py

# -----------------------------------------------
# This project should be completed using the
# Python programming language.
#
# Problem:
#----------
# Please parse the following URL into parts:
#     http://www.vandyhacks.org/dostuff/now
#
# While you've been given a specific URL
# Your solution should work for any valid
# URL.  Below is a skeleton and some test
# code.  You're job is to fill in the
# implmentation of the parse_url() function.
#
# parse_url() should return a python
# dictionary with the following keys
#
#    * scheme
#    * host
#    * path
#
# NOTE: there are a number of solutions to
# this problem including pre-built modules
# like urlparse.
#
# Your solution should display your ability
# to create efficient readable code that
# solves the problem without using pre-built
# libraries directly related to parsing URLs
#
# If you provide multiple ways to solve the
# problem that isn't a bad thing.
# -----------------------------------------------
the_url = "http://www.vandyhacks.org/dostuff/now";
simple_test = ['http://www.tutorialspoint.com/python/python_variable_types.htm', 'https://dev.twitter.com/cards/mobile/url-schemes','https://wordpress.com/stats/day/www.sirhamy.com::blog','https://twitter.com/',
               'http://first-news-app.readthedocs.org/en/latest/#act-5-hello-internet', 'http://www.poynter.org/2015/github-tutorials-and-resources-for-journalists/364387/', 'http://www.nltk.org/book/ch06.html',
               'https://docs.google.com/spreadsheets/d/1hefbuuYoYV7dxzdWgUrepVHhN9LrQtTJXh8i9carKuo/edit#gid=0', 'https://trello.com/b/XucTn63Y/school', 'https://gist.github.com/bmayes/bcdde36130ac797a4175', 'http://sirhamy.com'];

def parse_url(url):
    #  make sure your solution is valid 
    #  for NOT JUST the test URL. I will 
    #  be testing with others.
    
    # your code goes here.
    
    # do not solve using split()

    # unitl you add code execution will fail with 
    #  an 'IndentationError' until you start to fill 
    #  in this function.

    #Scheme always ends with ://
    schemePtr = url.find(":");

    #Check if host ends with final / or ? which happens after ://
    hostPtr = url.find("/", schemePtr+3);
    if(hostPtr == -1):
        hostPtr = url.find("?",schemePtr+3);

    url_dict = dict();
    url_dict['scheme'] = url[:schemePtr];

    if(hostPtr > schemePtr + 3):
        url_dict['host'] = url[schemePtr+3:hostPtr];
    else:
        url_dict['host'] = url[schemePtr+3:];

    #We don't want the initial / in our dictionary - according to tests
    #Also need to make sure that this exists
    if(hostPtr != -1):
        url_dict['path'] = url[hostPtr+1:];
    else:
        url_dict['path'] = "";

    print(url_dict['scheme']);
    print(url_dict['host']);
    print(url_dict['path']);
    
    return url_dict;












# -----------------------------------------------
#  TEST CODE AND MAIN
# -----------------------------------------------
def test_parse_url(url_dict):
    if type(url_dict) != dict:
        print "FAIL: you need to return a Dictionary from parse_url()"
        return

    the_keys = url_dict.keys()
    if not 'scheme' in the_keys:
        print "FAIL: your dictionary is missing the key 'scheme'"
        return

    if not 'host' in the_keys:
        print "FAIL: your dictionary is missing the key 'host'"
        return

    if not 'path' in the_keys:
        print "FAIL: your dictionary is missing the key 'path'"
        return

    if url_dict.get('scheme') != "http":
        print "FAIL: key: 'scheme' should be 'http'"
        return

    if url_dict.get('host') != "www.vandyhacks.org":
        print "FAIL: key: 'host' should be 'www.vandyhacks.org'"
        return

    if url_dict.get('path') != "dostuff/now":
        print "FAIL: key: 'path' should be 'dostuff/now'"
        return

    print "WELL DONE YOU PASSED -- !!"


parsed_url = parse_url(the_url)
test_parse_url(parsed_url)

#My test code
#for url in simple_test:
#    print("Orig URL: " + url);
#    parse_url(url);