Remove subsequent duplicates from list with keeping order.

del_duplicates_of_list.py

def remove_duplicates_of_list(lst):
    if len(lst) < 2:
        return lst
    d = {}
    for i in xrange(len(lst)):
        if lst[i] in d.values():
            continue
        d.update({i: lst[i]})
    return [lst[key] for key in sorted(d.keys())]

Hello I have an improvement
lst = list(set(lst)) does the job, is built-in and is way faster.

Try with a 500000 elements list :

a = range(0, 100000)
lst = []
for i in range(0, 5):
    lst.extend(a)
print len(lst)
print len(list(set(lst)))
print len(remove_duplicates_of_list(lst))

:-)