Created
February 23, 2014 05:37
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| vector<int>G[100]; | |
| void bfs(int n,int src) | |
| { | |
| queue<int>Q; | |
| Q.push(src); | |
| int visited[100]={0},level[100]; | |
| int parent[100]; | |
| visited[src]=1; | |
| level[src]=0; | |
| while(!Q.empty()) | |
| { | |
| int u=Q.front(); //Q এর সামনের নোড নিয়ে আমরা কাজ করবো | |
| for(int i=0;i<G[u].size();i++) | |
| { | |
| int v=G[u][i]; | |
| if(!visited[v]) | |
| { | |
| level[v]=level[u]+1; | |
| parent[v]=u; | |
| visited[v]=1; | |
| Q.push(v); | |
| } | |
| } | |
| Q.pop(); | |
| } | |
| for(int i=1;i<=n;i++) | |
| printf("%d to %d distance %d",src,i,level[i]); | |
| } |
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