Square root method in java

Square root

import java.util.Scanner;

public class SquareRoot {
	public static void main(String[] args) {
		String input;
		double sqrt,
		roundoff; //Declaring Variable
		System.out.println("To find Square Root"); //To print title Sq. root
		System.out.println("Enter a Number : "); //Asking user input
		Scanner keyboardInput = new Scanner(System. in ); //to get input
		input = keyboardInput.nextLine(); // Getting value in variable
		try {
			// checking valid integer using parseInt() method 		
			int number = Integer.parseInt(input);
			if (number >= 0) // To display Output
			{
				sqrt = Math.sqrt(number);
				roundoff = Math.round(sqrt * 100.0) / 100.0;
				System.out.println("Square root = " + roundoff);
			}
			else {
				System.out.println("Wrong Input! \n" + input + " is not a valid integer number ");
			}
		}
		catch(NumberFormatException e) {
			System.out.println("Wrong Input! \n" + input + " is not a valid integer number ");
		}
	}
}

The above square root method can find the sq. root of a number and if there is any wrong input (other than numeric value) it will show an error message