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code snippets for inverse chi-square distribution
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from scipy.stats.distributions import chi2 | |
chi2.ppf(0.95, df=5) # 11.07 |
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function mean_of_inversechi(v) { | |
if (v > 2) { | |
return 1/(v-2); | |
}else{ | |
return 0; | |
} | |
} | |
function variance_of_inversechi(v) { | |
if (v > 2) { | |
return 2/(Math.pow(v-2,2) * (v-4)); | |
}else{ | |
return 0; | |
} | |
} | |
function inverseChiSquarePDF(x, v) { | |
if (x <= 0 || v <= 0) { | |
throw new Error("Both x and degrees of freedom (v) must be greater than 0"); | |
} | |
const numerator = Math.pow(2, -v / 2); | |
const denominator = jStat.gammafn(v / 2); | |
const exponent = -1 / (2 * x); | |
const pdfValue = (numerator / denominator) * Math.pow(x, -(v / 2) - 1) * Math.exp(exponent); | |
return pdfValue; | |
} |
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library(VGAMextra) | |
xx <- seq(0, 3.0, len = 301) | |
yy <- dinv.chisq(xx, df = df) | |
qtl <- seq(0.1, 0.9, by = 0.1) | |
d.qtl <- qinv.chisq(qtl, df = df) | |
plot(xx, yy, type = "l", col = "orange", | |
main = "Orange is density, blue is cumulative distribution function", | |
sub = "Brown dashed lines represent the 10th, ... 90th percentiles", | |
las = 1, xlab = "x", ylab = "", ylim = c(0, 1)) | |
abline(h = 0, col= "navy", lty = 2) | |
lines(xx, pinv.chisq(xx, df = df), col = "blue") | |
lines(d.qtl, dinv.chisq(d.qtl, df = df), type ="h", col = "brown", lty = 3) |
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