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Recursively split directory of mp3s by X minute chunks. Requires ffmpeg.
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#!/bin/bash | |
min=10; #num minutes to split by | |
VERBOSE=false | |
QUIET=false | |
TEST=false | |
while getopts ':vqt:nh' opt; do | |
case $opt in | |
v) VERBOSE=true ;; | |
q) QUIET=true ;; | |
t) min=$OPTARG ;; | |
n) TEST=true ;; | |
h) echo "Split MP3 files"; echo "Options:"; | |
echo "-v verbose"; echo "-q quiet"; echo "-n noop - test mode"; | |
echo "-t specify a time in minutes to split by. Default is "$min; | |
exit 0; | |
;; | |
\?) echo "Unexpected option -$OPTARG" >&2; exit 1; ;; | |
:) echo "Option -$OPTARG requires an argument." >&2; exit 1; ;; | |
esac | |
done | |
# http://stackoverflow.com/questions/12199631/convert-seconds-to-hours-minutes-seconds-in-bash | |
convertsecs() { | |
((h=${1}/3600)) | |
((m=(${1}%3600)/60)) | |
((s=${1}%60)) | |
printf "%02d:%02d:%02d\n" $h $m $s | |
} | |
SAVEIFS=$IFS | |
IFS=$(echo -en "\n\b") | |
for file in $(find . -name '*.mp3' -type f -not -path '*/\.*'); do | |
#secLen=$(mdls "$file" | grep kMDItemDurationSeconds | awk '{print $3}') | |
secLen=$(ffmpeg -i "$file" -codec copy 2>&1 | grep Duration | awk '{split(gensub(/\,/,"","g",$2),a,":"); print (a[1]*60*60)+(a[2]*60)+(a[3])}') | |
splits=$(echo "($secLen/($min*60)) + 1" | bc ) | |
if [ $splits -lt 3 ]; then | |
$QUIET || echo "Skipping small file: $file" | |
continue | |
fi | |
$QUIET || echo 'Splitting file: '$file' | sec: '$secLen' | split: '$splits | |
X=0; while( [ $X -lt $splits ] ); do | |
start=$(convertsecs $((min*60*X))) | |
output="$(echo $file"_pt"$(($X+1))".mp3")" | |
$QUIET || $VERBOSE && echo "Split "$X" start: "$start | |
$TEST || ffmpeg -v quiet -i "$file" -acodec copy -t 00:$min:00 -ss $start "$output" | |
X=$((X+1)) | |
done; | |
#remove the orignal file | |
$TEST || rm "$file" | |
done; | |
IFS=$SAVEIFS |
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