Bash: Check the version of PHP

checkPHPVersion

#!/bin/bash
# Function to check if the PHP version is valid
checkPHPVersion() {

    # The current PHP Version of the machine
    PHPVersion=$(php -v|grep --only-matching --perl-regexp "5\.\\d+\.\\d+");
    # Truncate the string abit so we can do a binary comparison
    currentVersion=${PHPVersion::0-2};
    # The version to validate against
    minimumRequiredVersion=$1;
    # If the version match
    if [ $(echo " $currentVersion >= $minimumRequiredVersion" | bc) -eq 1 ]; then
        # Notify that the versions are matching
        echo "PHP Version is valid ...";
    else
        # Else notify that the version are not matching
        echo "PHP Version NOT valid for ${currentVersion} ...";
        # Kill the script
        exit 1
    fi

}

It doesn't work for anything but PHP 5 because it's hardcoded to look for versions starting with 5. However, switching the 5 out for a generic digit matches operating system information so you have to narrow the search to things preceeded by "PHP ". Then you have to trim them PHP part out of the result.

# The current PHP Version of the machine
PHPVersion=$(php -v|grep --only-matching --perl-regexp "(PHP )\d+\.\\d+\.\\d+");
echo $PHPVersion
# Truncate the string abit so we can do a binary comparison
currentVersion=${PHPVersion:4:3};

Thank you for the tip. I have modified it to use cut so that I can use it in a shell script. The final result is:
php -v|grep --only-matching --perl-regexp "(PHP )\d+\.\\d+\.\\d+"|cut -c 5-7

And I used it to create the following shell script:
https://gist.github.com/haljeshi/329a0fb0c6df43f3fc904d716a96af1b